document.write( "Question 1158412: Two towns are 1300 miles apart. A group of hikers start from each town and walk the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour faster than the other​ group, find the rate of each group. \n" ); document.write( "
Algebra.Com's Answer #781365 by josmiceli(19441)\"\" \"About 
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Add their rates of travel
\n" ); document.write( "Let \"+s+\" = the speed of the slower group in mi/hr
\n" ); document.write( "\"+1.5s+\" = the speed of the faster group in mi/hr
\n" ); document.write( "---------------------------
\n" ); document.write( "\"+1300+=+%28+s+%2B+1.5s+%29%2A200+\"
\n" ); document.write( "\"+6.5+=+2.5s+\"
\n" ); document.write( "\"+s+=+2.6+\"
\n" ); document.write( "and
\n" ); document.write( "\"+1.5s+=+1.5%2A2.6+\"
\n" ); document.write( "\"+1.5s+=+3.9+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "Their speeds are 2.6 mi/hr and 3.9 mi/hr
\n" ); document.write( "-----------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+1300+=+%28+s+%2B+1.5s+%29%2A200+\"
\n" ); document.write( "\"+1300+=+%28+2.6+%2B+3.9+%29%2A200+\"
\n" ); document.write( "\"+1300+=+6.5%2A200+\"
\n" ); document.write( "\"+1300+=+1300+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );