document.write( "Question 1158413: Lewiston and Vernonville are 128 miles apart. A car leaves Lewiston traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Lewiston. The car leaving Lewiston averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the cars? \n" ); document.write( "
Algebra.Com's Answer #781354 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the cars are traveling toward each other, their combined rate of speed is the sum of their rates of speed. Since the entire trip of 128 miles was completed in 1 hour and 36 minutes, which is to say 1.6 hours, the combined rate of speed must be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |