document.write( "Question 1158413: Lewiston and Vernonville are 128 miles apart. A car leaves Lewiston traveling towards​ Vernonville, and another car leaves Vernonville at the same​ time, traveling towards Lewiston. The car leaving Lewiston averages 10 miles per hour more than the​ other, and they meet after 1 hour and 36 minutes. What are the average speeds of the​ cars? \n" ); document.write( "
Algebra.Com's Answer #781354 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Since the cars are traveling toward each other, their combined rate of speed is the sum of their rates of speed. Since the entire trip of 128 miles was completed in 1 hour and 36 minutes, which is to say 1.6 hours, the combined rate of speed must be:\r
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\n" ); document.write( "\n" ); document.write( "Let represent the speed of the slower car, then must be the speed of the faster car, and the sum of these two quantities must be the combined speed, namely . In short:\r
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\n" ); document.write( "\n" ); document.write( "Solve for and then calculate
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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