document.write( "Question 1158377: Write the absolute value inequality in the form
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Algebra.Com's Answer #781317 by Edwin McCravy(20064) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Mark -5 and 7 on a number line with open circles since the inequalities\r\n" );
document.write( "are < and > and not < or > and graph the solution set.\r\n" );
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document.write( "<=========o-----------------------------------o========>\r\n" );
document.write( "-8 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4  5  6  7  8  9 10\r\n" );
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document.write( "Find the midpoint between -5 and 7 by averaging them:\r\n" );
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document.write( "Count how many units 1 is from -5 and from 7. (They should be the same\r\n" );
document.write( "if you got their average correctly)\r\n" );
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document.write( "I get (by counting units) that 1 is 6 units from both -5 and 7.\r\n" );
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document.write( "So we need to say this in symbols: \r\n" );
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document.write( "\"for a number x on the number line to be in the shaded part, the difference\r\n" );
document.write( "between it and the midpoint 1 (in absolute value) must be greater than 6 \r\n" );
document.write( "units.\"\r\n" );
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document.write( "To say that in symbols, we express the difference between x and 1 by \r\n" );
document.write( "indicating a subtraction of x and 1 with \"x-1\", and putting absolute\r\n" );
document.write( "values around it, like this |x-1| and indicating that it must be\r\n" );
document.write( "greater than 6 units away from the midpoint 1:\r\n" );
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document.write( "|x-1| > 6\r\n" );
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document.write( "Edwin

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