document.write( "Question 1158346: Money is invested at two rates of interest. One rate is 6% and the other is
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document.write( "2%.If there is $1200 more invested at 6% than at 2%, find the amount invested at each rate if the total annual interest received is $890.Let x=amount invested at
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document.write( "6% and y= amount invested at 2%.Then the system that models the problem is
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document.write( "{x=y+1200
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document.write( "0.06x+0.02y=890.Solve the system by using the method of addition. \n" );
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Algebra.Com's Answer #781270 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! (1) \n" ); document.write( "(2) \n" ); document.write( "-------------------------------- \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "------------------------------ \n" ); document.write( "Add (1) and (2) \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "------------------------------ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " |