document.write( "Question 1158342: Given two consecutive integers. The sum of four times the first integer and five times the second integer is 77. Find the integers \n" ); document.write( "

Algebra.Com's Answer #781264 by ikleyn(52908) $\"\"$ $\"About$

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document.write( "The consecutive integers are n and (n+1).\r\n" );
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document.write( "The equation, according to the condition, is\r\n" );
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document.write( "    4n + 5*(n+1) = 77.\r\n" );
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document.write( "It gives\r\n" );
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document.write( "    4n + 5n + 5 = 77\r\n" );
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document.write( "    9n          = 77 - 5 = 72\r\n" );
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document.write( "    n                    = 72/9 = 8.\r\n" );
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document.write( "ANSWER.  the integers are 8 and 9.\r\n" );
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\n" ); document.write( "\n" ); document.write( ". . . . . . . . \r
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\n" ); document.write( "\n" ); document.write( "Actually, this formulation is provocative.\r
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\n" ); document.write( "\n" ); document.write( "It is provocative, because the notion \"one number\" is not the same as the \"smaller number\".\r
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\n" ); document.write( "\n" ); document.write( "Therefore, in parallel with the equation (1), we should consider the other case\r
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\n" ); document.write( "\n" ); document.write( " 4*(n+1) + 5*n = 77.\r
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document.write( "It gives\r\n" );
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document.write( "    4n + 4 + 5n = 77\r\n" );
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document.write( "    9n          = 77 - 4  = 73\r\n" );
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document.write( "     n                    = 73/9  is not an integer number, so we reject this case.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Completed and solved.\r
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