document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158329>Question 1158329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Air passes through a duct at the rate of 680 cubic inches per second. How many cubic feet of air passes through the duct in 2.5 minutes? (round to the nearest cubic foot) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781248 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1728 in^3/ft^3 (12*12*12)<BR>\n" );
document.write( "so 680 in^3/sec*150 sec/2.5 min*1 ft^3/1728 in^3=59.03 or 59 ft^3\r<BR>\n" );
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document.write( "rough check. <BR>\n" );
document.write( "about 2.5 sec for 1 ft^3 of air<BR>\n" );
document.write( "150sec/2.5 ft^3/sec=60 ft^3 </SPAN>\n" );
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