document.write( "Question 1158317: Can you help me understand how to start/solve this number series problem?\r
\n" ); document.write( "\n" ); document.write( "(10 * 4/2), (12/4 * 2), (14 * 4/2), _________\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.
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Algebra.Com's Answer #781237 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "I assume (\"%2812%2F4%29+%2A+2\") should be (\"12%2A%284+%2F+2%29\") because in both other cases you multiply by \"4%2F2\"\r
\n" ); document.write( "\n" ); document.write( "(\"10+%2A+%284%2F2%29\"), (\"12%2A%284%2F2%29\"), (\"14+%2A+%284%2F2%29\"), _________simplify\r
\n" ); document.write( "\n" ); document.write( "(\"5+%2A+4\"), (\"6%2A4\"), (\"7+%2A+4\"), _________see pattern, \"5\",\"6\",\"7\" are multiplied by \"4\"; \r
\n" ); document.write( "\n" ); document.write( "so, next one will be (\"16%2A%284%2F2%29\")=(\"8%2A4\")\r
\n" ); document.write( "\n" ); document.write( "(\"20+\"), (\"24\"), (\"28\"), \"32\",......\r
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\n" ); document.write( "\n" ); document.write( "general formula:\r
\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D+=+4+%28n+%2B+4%29\" (for all terms given) where \"n\"=\"1\",\"2\",\"3\",....\r
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