document.write( "Question 1158315: It takes a smaller hose 4
\n" ); document.write( "times as long to fill a certain swimming pool as it does a larger hose. It takes both hoses working together 25
\n" ); document.write( "minutes to fill the pool. How long will it take the larger hose to fill the pool by itself?
\n" ); document.write( "

Algebra.Com's Answer #781226 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
It takes a smaller hose 4 times as long to fill a certain swimming pool as it does a larger hose.
\n" ); document.write( " It takes both hoses working together 25 minutes to fill the pool.
\n" ); document.write( " How long will it take the larger hose to fill the pool by itself?
\n" ); document.write( ":
\n" ); document.write( "Let t = time for the larger hose to fill the pool
\n" ); document.write( "then
\n" ); document.write( "4t = time for smaller hose to do the job
\n" ); document.write( "and
\n" ); document.write( "let the completed job = 1 (a full pool)
\n" ); document.write( ":
\n" ); document.write( "A typical shared work equation
\n" ); document.write( "each will do a fraction of the job, the two fractions add up 1
\n" ); document.write( "\"25%2Ft\" + \"25%2F%284t%29\" = 1
\n" ); document.write( "multiply by 4t, cancel out the denominators
\n" ); document.write( "4(25) + 25 = 4t
\n" ); document.write( "100 + 25 = 4t
\n" ); document.write( "t = 125/4
\n" ); document.write( "t = 31.25 min for the large hose to fill the pool
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( "\"25%2F31.5\" + \"25%2F%284%2831.5%29%29\" = 1
\n" ); document.write( "\"25%2F31.5\" + \"25%2F125\" = 1
\n" ); document.write( ".8 + .2 = 1
\n" ); document.write( "
\n" );