document.write( "Question 1158315: It takes a smaller hose 4
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document.write( "times as long to fill a certain swimming pool as it does a larger hose. It takes both hoses working together 25
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document.write( "minutes to fill the pool. How long will it take the larger hose to fill the pool by itself? \n" );
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Algebra.Com's Answer #781226 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! It takes a smaller hose 4 times as long to fill a certain swimming pool as it does a larger hose. \n" ); document.write( " It takes both hoses working together 25 minutes to fill the pool. \n" ); document.write( " How long will it take the larger hose to fill the pool by itself? \n" ); document.write( ": \n" ); document.write( "Let t = time for the larger hose to fill the pool \n" ); document.write( "then \n" ); document.write( "4t = time for smaller hose to do the job \n" ); document.write( "and \n" ); document.write( "let the completed job = 1 (a full pool) \n" ); document.write( ": \n" ); document.write( "A typical shared work equation \n" ); document.write( "each will do a fraction of the job, the two fractions add up 1 \n" ); document.write( " \n" ); document.write( "multiply by 4t, cancel out the denominators \n" ); document.write( "4(25) + 25 = 4t \n" ); document.write( "100 + 25 = 4t \n" ); document.write( "t = 125/4 \n" ); document.write( "t = 31.25 min for the large hose to fill the pool \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ".8 + .2 = 1 \n" ); document.write( " |