document.write( "Question 1158273: If today is Friday,
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document.write( "a. What day of the week will it be 25 days from now?
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document.write( "b. What day of the week was it 32 days ago? \n" );
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Algebra.Com's Answer #781207 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If today is Friday, then 7 days from now is also Friday. Same goes for 14 days, and 21 days. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have 25-21 = 4 days left over. Adding 4 days to Friday leads to Tuesday\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice how 25/7 = 3 remainder 4. That \"remainder 4\" bit is directly connected to adding those 4 days. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Tuesday\r \n" ); document.write( "\n" ); document.write( "========================================================== \n" ); document.write( "Part b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "32/7 = 4.57 approximately \n" ); document.write( "32 = 28+4 \n" ); document.write( "32 = 4*7+4 \n" ); document.write( "32 = 4*7+4 \n" ); document.write( "32/7 = 4 remainder 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Focus only on the remainder \n" ); document.write( "We will be subtracting 4 days from Friday since we are rewinding into the past this time. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Friday minus 4 days lands on Monday.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Monday\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |