document.write( "Question 1158252: Jon is 3 x Jacs age.
\n" ); document.write( "Jill is 1/3 of Jacs age.
\n" ); document.write( "Jon is 16 years older than Jill
\n" ); document.write( "How old is Jac? \n" ); document.write( "

Algebra.Com's Answer #781147 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "let Jon’s age be $\"x\"$ , Jac’s age $\"y\"$ , and Jill’s age $\"z\"$ \r
\n" ); document.write( "\n" ); document.write( "if Jon is $\"3\"$ times Jac’s age, we have\r
\n" ); document.write( "\n" ); document.write( " $\"x=3y\"$ .....eq.1\r
\n" ); document.write( "\n" ); document.write( "Jill is $\"1%2F3+\"$ of Jac’s age, we have\r
\n" ); document.write( "\n" ); document.write( " $\"z=%281%2F3%29y\"$ .....eq.2\r
\n" ); document.write( "\n" ); document.write( "if Jon is $\"16\"$ years older than Jill, we have\r
\n" ); document.write( "\n" ); document.write( " $\"x=z%2B16\"$ ....eq.3.......substitute $\"z\"$ from eq.2\r
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\n" ); document.write( "\n" ); document.write( " $\"x=%281%2F3%29y%2B16\"$ .......eq.3a\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.3a we have\r
\n" ); document.write( "\n" ); document.write( " $\"3y=%281%2F3%29y%2B16\"$ ........solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3y-%281%2F3%29y=16\"$ ....both sides multiply by $\"3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"9y-y=48\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"8y=48\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=6\"$ => Jac is $\"6\"$ years old\r
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