document.write( "Question 1158217: A printer is printing out 3-digit numbers between 100-999 such that the digits are not repeated.
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document.write( "(a) If 2000 such numbers are printed out, at least how many of them will be identical? Justify your
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document.write( "answer.
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document.write( "(b) At least how many of the numbers should be printed, so that at least 3 of them will be identical?
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document.write( "Justify your answer.
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document.write( "(c) At least how many of the numbers should be printed, so that the number 243 is printed at least 6
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document.write( "times? Justify your answer.
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Algebra.Com's Answer #781145 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A printer is printing out 3-digit numbers between 100-999 such that the digits are not repeated. \n" ); document.write( "(a) If 2000 such numbers are printed out, at least how many of them will be identical? Justify your answer. \n" ); document.write( "(b) At least how many of the numbers should be printed, so that at least 3 of them will be identical? Justify your answer. \n" ); document.write( "(c) At least how many of the numbers should be printed, so that the number 243 is printed at least 6 times? Justify your answer. \n" ); document.write( "~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "First, we need estimate, how many such 3-digit numbers between 100 and 999 (inclusive) do exist\r\n" ); document.write( "such that the digits are not repeated.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "This maximal possible amount of such numbers is 9*8*7 = 504.\r\n" ); document.write( "\r\n" ); document.write( " (any of 9 digits from 1 to 9 in the 1-st position;\r\n" ); document.write( " any of 8 remaining digits in the 2-nd position; and\r\n" ); document.write( " any of 7 remaining digits in the 3-rd position).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(a) If 2000 such numbers are printed out, at least how many of them will be identical ?/.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now, I state that of 2000 such printed numbers, there are at least 3 (three) identical numbers.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Indeed, if any printed number is repeating less than 3 times, than the total amount of printed instances \r\n" ); document.write( " would be not more than 3*504 = 1512; but in reality, we have 2000 (!) printed numbers.\r\n" ); document.write( "\r\n" ); document.write( " Thus the ANSWER to question (a) is 3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) At least how many of the numbers should be printed, so that at least 3 of them will be identical ?\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " From the logic of my solutions to (a), it is clear, that at least 3*504+1 = 1513 such numbers should be printed, \r\n" ); document.write( " so that at least 3 of them will be identical. \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Thus the ANSWER to question (b) is 3*504+1 = 1513.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) At least how many of the numbers should be printed, so that the number 243 is printed at least 6 times ?\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " This question is posed INCORRECTLY: infinitely many such numbers can be printed, NO ONE of which is the number 243.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The principle of proving such statements/(solving such problems) is called \"the pigeonhole principle\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See the lesson\r \n" ); document.write( "\n" ); document.write( " - The \"pigeonhole principle\" problems \r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |