document.write( "Question 1158190: Verify that A = (7, 4), B = (−7, 4), C = (−1, −8), and D = (8, −1) all lie on a circle centered at the origin. Let K be the intersection of chords AC and BD. Prove that triangles KAB and KDC are similar and find the ratio of similarity. Then, show that KA · KC = KB · KD.
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Algebra.Com's Answer #781118 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) For each of the points, the distance from the origin is sqrt(65). \n" ); document.write( "(2) Angles A and D are congruent because they both cut off arc BC; angles B and C are congruent because they both cut off arc AD. Two pairs of congruent angles makes the triangles similar. \n" ); document.write( "(3) The lengths of corresponding sides AB and CD are 14 and sqrt(130), so the ratio of similarity is 14:sqrt(130). \n" ); document.write( "(4) KA*KC = KB*KD by the theorem about the lengths of the pieces of two intersecting chords. Or you can prove it using the two similar triangles. \n" ); document.write( " \n" ); document.write( " |