document.write( "Question 1158205: A random sample of 42 college graduates revealed that they worked an average of 5.5 years on the job before being promoted. The sample standard deviation was 1.1 years. Using the 0.99 degree of confidence, what is the confidence interval for the population mean?.....A. 5.04 and 5.96
\n" ); document.write( "B. 5.06 and 5.94
\n" ); document.write( "C. 2.67 and 8.33
\n" ); document.write( "D. 4.40 and 6.6
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Algebra.Com's Answer #781110 by Boreal(15235)\"\" \"About 
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half-interval is t(0.995)*s/sqrt(n)
\n" ); document.write( "=2.70*1.1/sqrt(42)=0.458 is half interval so full interval is 0.916
\n" ); document.write( "(5.04, 5.96)
\n" ); document.write( "A.
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