document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158207>Question 1158207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mark can dig a ditch in 4 hours. Greg can dig the same ditch in 3 hours. How long would it take them to dig it together? PLEASE PROVIDE FULL ANSWER!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #781103 by </B><A HREF=/tutors/aboutme.mpl?userid=VFBundy><B>VFBundy(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=VFBundy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=VFBundy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=781103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mark's rate of work = 1/4 ditch per hour<BR>\n" );
document.write( "Greg's rate of work = 1/3 ditch per hour<BR>\n" );
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document.write( "Rate of work working together = (1/4 + 1/3) ditch per hour = (3/12 + 4/12) ditch per hour = 7/12 ditch per hour<BR>\n" );
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document.write( "If they can dig 7/12 of the ditch per hour working together, this means it will take them 12/7 hour to dig the ditch working together.<BR>\n" );
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document.write( "12/7 hours...or 1-5/7 hours...is about 1 hour and 43 minutes. </SPAN>\n" );
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