document.write( "Question 1158097: What is the total number of different 10-letter arrangements that can be formed using the letters in the word ABSTEMIOUS?
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Algebra.Com's Answer #781011 by ikleyn(52780)\"\" \"About 
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document.write( "There are 10 letter in the word.\r\n" );
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document.write( "They all are UNIQUE, except one letter \" S \", which has multiplicity of 2.\r\n" );
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document.write( "Therefore, the number of all distinguishable arrangements of the letters is  \"10%21%2F2%21\" = \"3%2A4%2A5%2A6%2A7%2A8%2A9%2A10\" = 1814400.    ANSWER\r\n" );
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document.write( "2! in the formula serves to account for repeation letter \" E \".\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see other similar solved problems,  look into the lesson\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic  \"Combinatorics: Combinations and permutations\". \r
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\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
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