document.write( "Question 1971: Solve for x e^(2In(2x)) = 4 \n" ); document.write( "
Algebra.Com's Answer #781 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"e%5E%282ln%282x%29%29+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Take logs of both sides, to remove the e power\r
\n" ); document.write( "\n" ); document.write( "2ln(2x) = ln4
\n" ); document.write( "2ln(2x) = ln\"2%5E2\"
\n" ); document.write( "2ln(2x) = 2ln2
\n" ); document.write( "ln(2x) = ln2\r
\n" ); document.write( "\n" ); document.write( "raise everything to power of e, to remove the logs\r
\n" ); document.write( "\n" ); document.write( "2x = 2
\n" ); document.write( "x=1\r
\n" ); document.write( "\n" ); document.write( "CHECK...always a good thing to do.\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%282ln%282%29%29\" plug this into your calculator and you get 4, so x=1 is correct.\r
\n" ); document.write( "\n" ); document.write( "or manually :-): \"e%5E%28ln%282%5E2%29%29\" --> \"e%5E%28ln%284%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Now, \"e%5E%28ln%28x%29%29\" just leaves x, so ours just leaves the 4 --> the answer\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "jon
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