document.write( "Question 1158062: Six years ago, Joe Foster was two years more than five times as old as his daughter. Six years from now,
\n" ); document.write( "he will be 11 years more than twice as old as she will be. How old is Joe?
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Algebra.Com's Answer #780994 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let j = Joe's present age
\n" ); document.write( "let d = daughter's
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "Six years ago, Joe Foster was two years more than five times as old as his daughter.
\n" ); document.write( "j - 6 = 5(d-6) + 2
\n" ); document.write( "j - 6 = 5d - 30 + 2
\n" ); document.write( "j = 5d - 28 + 6
\n" ); document.write( "j = 5d - 22
\n" ); document.write( " Six years from now, he will be 11 years more than twice as old as she will be.
\n" ); document.write( "j + 6 = 2(d+6) + 11
\n" ); document.write( "j + 6 = 2d + 12 + 11
\n" ); document.write( "j = 2d + 23 - 6
\n" ); document.write( "j = 2d + 17
\n" ); document.write( "Replace j with (5d-22) from the 1st statement
\n" ); document.write( "5d - 22 = 2d + 17
\n" ); document.write( "5d - 2d = 17 + 22
\n" ); document.write( "3d = 39
\n" ); document.write( "d = 39/3
\n" ); document.write( "d = 13 yrs is the daughter's age
\n" ); document.write( "Find j
\n" ); document.write( "j = 5(13) - 22
\n" ); document.write( "j = 65 - 22
\n" ); document.write( "j = 43 is Joe's age
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\n" ); document.write( "See if this checks out in the statement
\n" ); document.write( "\"Six years ago, Joe Foster was two years more than five times as old as his daughter.\"
\n" ); document.write( "43 - 6 = 5(13 - 6) + 2
\n" ); document.write( "37 = 5(7) + 2 \n" ); document.write( "
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