document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1158058>Question 1158058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the exact solutions of cos theta if sin theta = 3/4 pi/2 is less than or equal to theta and theta is less than or equal to pi<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780982 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "I think the other tutor misinterpreted the question because it was presented poorly.<br><BR>\n" );
document.write( "I think the problem is to find cos(theta) if sin(theta) = 3/4 AND theta is between pi/2 and pi.<br><BR>\n" );
document.write( "theta between pi/2 and pi means 2nd quadrant, where cosine is  negative.<br><BR>\n" );
document.write( "Then sin^2+cos^2=1 gives us |cos(theta)| = sqrt(7)/4; and since cosine is negative in quadrant II....<br><BR>\n" );
document.write( "ANSWER: cos(theta) = -sqrt(7)/4<br><BR>\n" );
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