document.write( "Question 1158034: Twelve different video games showing substance use were observed and the duration times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the data to construct a 99% confidence interval estimate of mu, the mean duration of game play.
\n" );
document.write( "4057
\n" );
document.write( "3882
\n" );
document.write( "3863
\n" );
document.write( "4032
\n" );
document.write( "4321
\n" );
document.write( "4811
\n" );
document.write( "4653
\n" );
document.write( "4028
\n" );
document.write( "5001
\n" );
document.write( "4816
\n" );
document.write( "4325
\n" );
document.write( "4316 \n" );
document.write( "
Algebra.Com's Answer #780956 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the 99%CI is x bar +/- t (0.995, df=11)*s/sqrt(n), where n=12\r \n" ); document.write( "\n" ); document.write( "t=3.106 \n" ); document.write( "x bar=4342.08 \n" ); document.write( "s=392.43 \n" ); document.write( "half-interval is 351.96 \n" ); document.write( "(3990.12, 4694.04) is 99% CI of the true mean or (3990, 4694) \n" ); document.write( " \n" ); document.write( " |