document.write( "Question 1157986: A kite has an 8-inch side and a 15-inch side, which form a right angle. Find the length of the diagonals of the kite. \n" ); document.write( "
Algebra.Com's Answer #780921 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"kite.png\"\r
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\n" ); document.write( "\n" ); document.write( "In order to solve this problem, first observe that the red diagonal line divides the kite into two triangles that each have side lengths of \"15\" and \"8\". Notice, the hypotenuse of the interior triangle is the red diagonal. Therefore, use the Pythagorean theorem: \r
\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\", where \"c\"= the length of the red diagonal. \r
\n" ); document.write( "\n" ); document.write( "The solution is: \r
\n" ); document.write( "\n" ); document.write( "\"8%5E2%2B15%5E2=c%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"64%2B225=c%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=289\"\r
\n" ); document.write( "\n" ); document.write( "\"c=sqrt%28289%29\"\r
\n" ); document.write( "\n" ); document.write( "\"c=17in+\"\r
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\n" ); document.write( "the other diagonal \"d\":\r
\n" ); document.write( "\n" ); document.write( "recall that the area of a kite is half the product of the diagonals \r
\n" ); document.write( "\n" ); document.write( "\"A=c%2Ad%2F2\"....since \"c=17\"\r
\n" ); document.write( "\n" ); document.write( "\"A=17%2Ad%2F2\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "The diagonals of the kite are the height and width of the \"rectangle\" it is superimposed in, and we know that because the area of a rectangle is base times height.\r
\n" ); document.write( "\n" ); document.write( "Therefore the area of a rectangle is:\r
\n" ); document.write( "\n" ); document.write( "\"A=15%2A8=15%2A4=120\"\r
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\n" ); document.write( "\n" ); document.write( "substitute in the area of a kite:\r
\n" ); document.write( "\n" ); document.write( "\"120=17%2Ad%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"240=17d\"\r
\n" ); document.write( "\n" ); document.write( "\"d=240%2F17\"\r
\n" ); document.write( "\n" ); document.write( "\"d=14.118in\"\r
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