document.write( "Question 1158001: How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 60 liters of a 65% acid solution? (Round to two decimal places if necessary.) \n" ); document.write( "
Algebra.Com's Answer #780918 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! If you start with v for how much of 75%, and 60-v for how much 50%, you can form equation \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can see in this solution formula a possible easy way to form a necessary fraction, to multiply by the mixture size of 60L.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "--\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "More generally for two-part mixture,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "H, the high concentration percent \n" ); document.write( "L, the low conc percent \n" ); document.write( "T, target conc. percent \n" ); document.write( "M, the size of result mixture \n" ); document.write( "v, amount of the H material\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and solving this for v will give\r \n" ); document.write( "\n" ); document.write( " |