document.write( "Question 1158001: How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 60 liters of a 65% acid solution? (Round to two decimal places if necessary.) \n" ); document.write( "
Algebra.Com's Answer #780918 by josgarithmetic(39617)\"\" \"About 
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If you start with v for how much of 75%, and 60-v for how much 50%, you can form equation \"75v%2B50%2860-v%29=65%2A60\", from which you will find:\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28v=60%28%2865-50%29%2F%2875-50%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can see in this solution formula a possible easy way to form a necessary fraction, to multiply by the mixture size of 60L.\r
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\n" ); document.write( "\n" ); document.write( "More generally for two-part mixture,\r
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\n" ); document.write( "\n" ); document.write( "H, the high concentration percent
\n" ); document.write( "L, the low conc percent
\n" ); document.write( "T, target conc. percent
\n" ); document.write( "M, the size of result mixture
\n" ); document.write( "v, amount of the H material\r
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\n" ); document.write( "\n" ); document.write( "\"Hv%2BL%28M-v%29=TM\"\r
\n" ); document.write( "\n" ); document.write( "and solving this for v will give\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28v=M%28%28T-L%29%2F%28H-L%29%29%29\"
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