document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157945>Question 1157945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A surgery conducted that asked 1015 people how many books they had read in the last year. Results indicated that x=13.7 and s=16.6 books. Construct a 99% confidence interval for the mean number of books people read. Interpret the interval </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780876 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 99%CI half-interval is t(0.995,df=1015)*s/sqrt(n).   {it is a survey}<BR>\n" );
document.write( "=2.581*16.6/sqrt(1015)<BR>\n" );
document.write( "=1.34<BR>\n" );
document.write( "the interval is (12.36, 15.04)<BR>\n" );
document.write( "probably should round to (12.4, 15.0) units books\r<BR>\n" );
document.write( "\n" );
document.write( "That means while we don't know the average number of books all people have read in the past year, we are 99% confident that the true number lies in the interval (12.4, 15.0)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );