document.write( "Question 1157864: 1) A poll was done where 450 adults were randomly surveyed. 35 % said they were working hard at their jobs and hoped to get a promotion. Calculate and interpret a 95 % confidence interval for the proportion of adults who said they were working hard and hoped for a promotion.
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Algebra.Com's Answer #780865 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "x = 0.35*450 = 157.5, which is not a whole number of people, so we round up to\r\n" );
document.write( "158.  (some teachers say to round down.  You'll have to ask your teacher. Maybe\r\n" );
document.write( "he or she wants you to round down to 157. It will make a difference in the third\r\n" );
document.write( "decimal place of the interval bounds.) \r\n" );
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document.write( "On your TI-84\r\n" );
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document.write( "Press STAT\r\n" );
document.write( "Press right arrow key to highlight TESTS\r\n" );
document.write( "Scroll down with down arrow key to 1-PropZInt...\r\n" );
document.write( "Press ENTER\r\n" );
document.write( "Make the screen read like this:\r\n" );
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document.write( "       1-PropZInt        \r\n" );
document.write( "x:158\r\n" );
document.write( "n:450\r\n" );
document.write( "C-Level:0.95\r\n" );
document.write( "Calculate\r\n" );
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document.write( "Use down arrow to highlight Calculate\r\n" );
document.write( "Press ENTER\r\n" );
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document.write( "Read\r\n" );
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document.write( "(0.30701,0.39521)\r\n" );
document.write( "p̂=0.3511111111\r\n" );
document.write( "n-450\r\n" );
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document.write( "The confidence interval is 0.30701 < p < 0.39521\r\n" );
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document.write( "Edwin
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