document.write( "Question 1157943: A private jet flies the same distance in 15 hours that a commercial jet flies in 10 hours. If the speed of the commercial jet was 98mph less than 2 times the speed of the private jet, find the speed of each jet. \n" ); document.write( "
Algebra.Com's Answer #780852 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "private jet's speed = 196 mph \n" ); document.write( "commercial jet's speed = 294 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===========================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = speed of private jet \n" ); document.write( "c = speed of commercial jet \n" ); document.write( "speeds are in mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\" the speed of the commercial jet was 98mph less than 2 times the speed of the private jet\" \n" ); document.write( "So, \n" ); document.write( "c = 2p-98\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The private jet travels some distance d miles in t = 15 hours \n" ); document.write( "distance = rate*time \n" ); document.write( "d = r*t \n" ); document.write( "d = p*15 \n" ); document.write( "d = 15p\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and the commercial jet travels that same distance in t = 10 hours \n" ); document.write( "d = r*t \n" ); document.write( "d = c*10 \n" ); document.write( "d = 10c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We're referring to the same distance d value, so we can equate the two right hand sides of the equations above \n" ); document.write( "15p = 10c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now plug in c = 2p-98 \n" ); document.write( "15p = 10c \n" ); document.write( "15p = 10( c ) \n" ); document.write( "15p = 10( 2p-98 ) ... c has been replaced with 2p-98 \n" ); document.write( "15p = 20p - 980 .... distribute \n" ); document.write( "15p-20p = -980 .... subtract 20p from both sides \n" ); document.write( "-5p = -980 \n" ); document.write( "p = -980/(-5) .... divide both sides by -5 \n" ); document.write( "p = 196\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this value of p to find the value of c \n" ); document.write( "c = 2p - 98 \n" ); document.write( "c = 2*196 - 98 ... replace p with 196 \n" ); document.write( "c = 392 - 98 \n" ); document.write( "c = 294\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In summary, we found: \n" ); document.write( "p = 196 \n" ); document.write( "c = 294 \n" ); document.write( "meaning the private jet travels a speed of 196 mph and the commercial jet travels a speed of 294 mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |