document.write( "Question 1157939: The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term? \r
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\n" ); document.write( "\n" ); document.write( "Fr solving this question, I feel that there's a problem with the question. Do you agree pls.
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Algebra.Com's Answer #780842 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "The second and fifth term of a GP are 3/2 and 1/12, respectively. What is the first term?
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\n" ); document.write( "\n" ); document.write( "\"system%28T%5B2%5D=3%2F2%2Cand%2CT%5B5%5D=1%2F12%29\"\r
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\n" ); document.write( "\n" ); document.write( "common ratio unknown but can be found. Then \"T%5B2%5Dr%5E3=T%5B5%5D\". Maybe you can find this r, and do the rest.\r
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\n" ); document.write( "\n" ); document.write( "Do the substitutions and then the algebra steps, and you may find \"r=root%283%2C12%29%2F6\".
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