document.write( "Question 1157932: A drawer contains 12 red socks and 8 black socks. Suppose that you choose 2 socks at random in the dark. What is the probability that you get a pair of red socks? \r
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document.write( "A drawer contains 12 red socks and 8 black socks. Suppose that you choose 2 socks at random in the dark. What is the probability that you get a pair of black socks? \r
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document.write( "A drawer contains 12 red socks and 8 black socks. Suppose that you choose 2 socks at random in the dark. What is the probability that you do not get a pair of socks?\r
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document.write( "i missed this lesson on my google meet, hoping i can get some help, thanks\r
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Algebra.Com's Answer #780832 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I don't know what method(s) might have been taught at the meet you missed.... \n" ); document.write( "One way to work relatively simple problems like this is to use the probabilities that each sock drawn one at a time will give the desired outcome. \n" ); document.write( "For getting a pair of red socks, the probability that the first is red is 12/20 and the probability the second is also red is 11/19. The probability of a pair of red socks is then (12/20)(11/19) = 132/380. Simplify the fraction, or express as a decimal, if necessary. \n" ); document.write( "Use the same method to find the probability of getting a pair of black socks. \n" ); document.write( "For getting two socks that don't match, you need to consider two possibilities: black then red, and red then black. \n" ); document.write( "P(black, red = (8/20)(12/19) = 96/380 \n" ); document.write( "P(red, black) = (12/20)(8/19) = 96/380 \n" ); document.write( "So P(unmatched pair) = 192/380 \n" ); document.write( "Note that the three cases -- a pair of red, a pair of black, and an unmatched pair -- are all the possibilities, so the sum of the probabilities for the three cases should be 1. \n" ); document.write( "As problems like this get more complicated, that method quickly becomes very awkward; a more sophisticated method is much easier. \n" ); document.write( "Instead of calculating probabilities for each draw, we use the basic definition of probability for the whole desired outcome. \n" ); document.write( "For example, for drawing a pair of red socks, the probability is \r\n" ); document.write( " number of ways of drawing 2 of the 12 red socks (and 0 of the 8 black)\r\n" ); document.write( " ------------------------------------------------------------------------\r\n" ); document.write( " total number of ways of drawing 2 of the 20 socks \n" ); document.write( "The numerator is \"12 choose 2\"; the denominator is \"20 choose 2\": \n" ); document.write( " \n" ); document.write( "And for getting an unmatched pair, the numerator is \"12 choose 1 AND 8 choose 1\": \n" ); document.write( " \n" ); document.write( "You can use this method for calculating the probability of getting a pair of red socks. \n" ); document.write( "Of course for each of the three outcomes, your answers should be the same by both methods. \n" ); document.write( " \n" ); document.write( " |