document.write( "Question 107112This question is from textbook Beginning Algebra
\n" ); document.write( ": The Length of a rectangular label is three times its width. If the length is decreased by 1 while the width stayed the same, the area of the new label would be 44 square centimeters. Find the original length and the width of the label. \n" ); document.write( "
Algebra.Com's Answer #78079 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let W=width of label
\n" ); document.write( "Then Length(L)=3W
\n" ); document.write( "Length decreased by DISABLED_event_one= 3W-1
\n" ); document.write( "Area(A)=L*W
\n" ); document.write( "In this problem, W=W and L=(3W-1), So:\r
\n" ); document.write( "\n" ); document.write( "A=W(3W-1)=44 get rid of parens (distributive law)
\n" ); document.write( "3W^2-W=44 subtract 44 from both sides\r
\n" ); document.write( "\n" ); document.write( "3W^2-W-44=44-44 collect like terms\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-W-44=0\" quadratic in standard form and it can be factored:
\n" ); document.write( "(Note: How did I know that it could be factored??? First, I calculated
\n" ); document.write( "\"sqrt%28b%5E2-4a%2Ac%29\"and found it to be \"sqrt%28529%29\" or \"23\" which tells me that it can probably be factored. Next, I commenced evaluating the possible factors (a total of eight possibilities) until I found the one that worked.)\r
\n" ); document.write( "\n" ); document.write( "\"%283W%2B11%29%28W-4%29=0\", so:
\n" ); document.write( "\"3W%2B11=0\"
\n" ); document.write( "\"3W=-11\"----------------------disregard negative value for width
\n" ); document.write( "and:\r
\n" ); document.write( "\n" ); document.write( "\"w-4=0\"
\n" ); document.write( "\"W=4\"cm------------------width
\n" ); document.write( "\"3W=3%2A4=12\" cm--------------------------original length\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "4*(12-1)=44
\n" ); document.write( "4*11=44
\n" ); document.write( "44=44\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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