document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157874>Question 1157874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trees planted by a landscaping firm have a 90% one-year survival rate. If they plant 12 trees in a park, what is the following probabilities:<BR>\n" );
document.write( "1. All the trees survive one year. <BR>\n" );
document.write( "2. At least 10 trees survive one year. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780778 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. this has .90^12 probability or 0.2824<BR>\n" );
document.write( "2. this means 10,11,or 12 trees survive<BR>\n" );
document.write( "Can use the calculator or do it by hand for 10 and 11<BR>\n" );
document.write( "for 10 it is 12C10^0.9^10*0.1^2=0.2301<BR>\n" );
document.write( "for 11 It is 12*.9^11*.1=0.3766<BR>\n" );
document.write( "the sum of those three is 0.8891\r<BR>\n" );
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document.write( "calculator do 1-binomcdf(12,.9,9), the calculator can only do the left side of the binomial, which isn't what we want.  We find the cumulative probability of 0 to 9 trees and subtract that from 1 to get the probability we want,. </SPAN>\n" );
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