document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157869>Question 1157869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The denominator of a fraction is two more than the numerator. If both numerator and denominator are increased by ten, the simplified result is 9/10. Find the original fraction. (Do NOT simplify.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780758 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the fraction be (x)/(x+2)<BR>\n" );
document.write( "the new one is (x+10)/(x+12)=9/10<BR>\n" );
document.write( "cross-multiply <BR>\n" );
document.write( "9(x+12)=10(x+10)<BR>\n" );
document.write( "9x+108=10x+100<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "x+2=10<BR>\n" );
document.write( "(8/10) is the fraction<BR>\n" );
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