document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107266>Question 107266</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937760/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> how do you find the slope of the graph of the liner function f?<BR>\n" );
document.write( "f(2) = -3, f(-2) = 5<BR>\n" );
document.write( "how do you find the slope of the graph of the liner function f?<BR>\n" );
document.write( "f(0) = 4, f(4) = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78075 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a linear graph has the form y=mx+b<BR>\n" );
document.write( "f(2)=-3 means that when x=2, y=-3\r<BR>\n" );
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document.write( "so wehave -3=2m+b\r<BR>\n" );
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document.write( "f(-2)=5 means that when x=-2, y=5\r<BR>\n" );
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document.write( "so we have 5=-2m+b\r<BR>\n" );
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document.write( "we solve these simulateously<BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++2%5Cm+%2B+1%5Cb+=+-3%2C%0D%0A++++-2%5Cm+%2B+1%5Cb+=+5+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++2%5Cm+%2B+1%5Cb+=+-3%2C%0D%0A++++-2%5Cm+%2B+1%5Cb+=+5+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving 1*b to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Am+=+-3+-+1%2Ab ALIGN=MIDDLE  ALT=\"2%2Am+=+-3+-+1%2Ab\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+-3%2F2+-+1%2Ab%2F2 ALIGN=MIDDLE  ALT=\"m+=+-3%2F2+-+1%2Ab%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2A%28-3%2F2+-+1%2Ab%2F2%29+%2B+1%5Cb+=+5 ALIGN=MIDDLE  ALT=\"-2%2A%28-3%2F2+-+1%2Ab%2F2%29+%2B+1%5Cb+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that b=1. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+-3%2F2+-+1%2Ab%2F2 ALIGN=MIDDLE  ALT=\"m+=+-3%2F2+-+1%2Ab%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, m=-2.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+m=-2%2C+b=1+%29 ALIGN=MIDDLE  ALT=\"system%28+m=-2%2C+b=1+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE><BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );