document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157784>Question 1157784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves Berlin at 3:00PM with a speed of 85 km/h towards the north. Another train leaves at the same time from the same station towards the south with a speed of 95 km/h. How long (time in minutes) will it take before they are separated by 630 kilometers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780656 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Their combined speed is directly apart at 85+95=180 km/h<BR>\n" );
document.write( "630 km/180 km/h=3.5 hours <BR>\n" );
document.write( "or 210 minutes.\r<BR>\n" );
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document.write( "Also, 180 km/h is 3 km/minute and 630km /3 km/min=210 min </SPAN>\n" );
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