document.write( "Question 1157749: suppose that the value of a stock varies each day from $12 to $27 with a uniform distribution . Find the probability that the stock is less than $22 given that the stock is greater than $16. \n" ); document.write( "
Algebra.Com's Answer #780634 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer in fraction form = 6/11 \n" ); document.write( "Approximate answer in decimal form = 0.54545 \n" ); document.write( "Approximate answer in percent form = 54.545%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "================================================================================\r \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The uniform distribution is graphed as a rectangle. In this problem, the base of the rectangle goes from 12 to 27, which is a distance of 27-12 = 15 units. The height must be 1/15 to ensure that the area of the rectangle is 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area = base*height \n" ); document.write( "area = 15*(1/15) \n" ); document.write( "area = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The unit 1 refers to 100% probability\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are told that \"given that the stock is greater than $16.\" which means we only focus on the portion of the rectangle from 16 to 27. The base is now 27-16 = 11 while the height remains the same\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area = base*height \n" ); document.write( "area = 11*(1/15) \n" ); document.write( "area = 11/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we were to throw a random dart at the entire distribution, then the probability of landing on a stock price larger than $16 is 11/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let A = 11/15, which we'll use later.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we ask to find \"the probability that the stock is less than $22\". Keep in mind that we know the stock is greater than $16, so we consider the range from 16 to 22 which has a base of 22-16 = 6 and a height of 1/15, so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area = base*height \n" ); document.write( "area = 6*(1/15) \n" ); document.write( "area = 6/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let B = 6/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now divide B over A to get the conditional probability we're after\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B/A = (6/15) divided by (11/15) \n" ); document.write( "B/A = (6/15) * (15/11) \n" ); document.write( "B/A = (6*15)/(15*11) \n" ); document.write( "B/A = 6/11 \n" ); document.write( "B/A = 0.54545 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's a visual. We know the stock is above $16, which is represented by this shaded red portion below \n" ); document.write( " ![]() \n" ); document.write( "This red rectangle has base 11 and height 1/15, so its area is 11/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we want to find the probability of throwing a random dart in the purple region, then we would divide the purple rectangle area over the red rectangle area (from the above figure) \n" ); document.write( " ![]() \n" ); document.write( "This purple rectangle has base 6 and height 1/15, so its area is 6/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, \n" ); document.write( "answer = (area of purple rectangle)/(area of red rectangle) \n" ); document.write( "answer = (area of rectangle BCFG)/(area of BDEG) \n" ); document.write( "answer = (6/15)/(11/15) \n" ); document.write( "answer = 6/11 \n" ); document.write( "answer = 0.54545 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------\r \n" ); document.write( "\n" ); document.write( "Another approach:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note how the rectangle ADEH is divided into 15*4 = 60 smaller rectangles because of the dashed grid lines \n" ); document.write( "6*4 = 24 smaller rectangles are painted purple \n" ); document.write( "11*4 = 44 smaller rectangles are painted red \n" ); document.write( "24/44 = 6/11 represents the probability of throwing a random dart in the purple region given we know the dart landed in the red region. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------\r \n" ); document.write( "\n" ); document.write( "Yet another approach:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide the length of BC over BD \n" ); document.write( "answer = (length of BC)/(length of BD) \n" ); document.write( "answer = 6/11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the fastest method, but it does not use the rectangular uniform distribution. So it will depend on what your teacher wants you to show. \n" ); document.write( " \n" ); document.write( " |