document.write( "Question 1157710: A person removes two aces and a king from a deck of 52 playing cards, and draws, without replacement,
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document.write( "two more cards from the deck. Find the probability that the person will draw two aces, two kings, or an ace and then a king. (In that last case, the ace is first, and the king is second. \n" );
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Algebra.Com's Answer #780611 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "So there are 49 cards left in the deck.... \n" ); document.write( "P(ace, ace) = (2/49)(1/48) = 2/2352 \n" ); document.write( "P(king, king) = (4/49)(3/48) = 12/2352 \n" ); document.write( "P(ace, king) = (2/49)(4/48) = 8/2352 \n" ); document.write( "P(any one of those three outcomes) = 22/2352 \n" ); document.write( "Simplify or convert to decimal if required. \n" ); document.write( " \n" ); document.write( " |