document.write( "Question 1157684: Three dice are tossed. Find the probability of rolling a sum greater than 5. \n" ); document.write( "
Algebra.Com's Answer #780573 by ikleyn(52790)\"\" \"About 
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document.write( "The entire space of events has  6*6*6 = 216 elements/(events) with the probability \"1%2F216\"  each.\r\n" );
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document.write( "Of them undesired are\r\n" );
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document.write( "    1 event  with the sum of 3   [ the event (1,1,1) ]\r\n" );
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document.write( "    3 events with the sum of 4   [ the events (1,1,2), (1,2,1)  and (2,1,1) ]\r\n" );
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document.write( "    6 events with the sum of 5   [ the events (1,1,3), (1,3,1), (3,1,1),\r\n" );
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document.write( "                                              (1,2,2), (2,1,2), (2,2,1) ].\r\n" );
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document.write( "The rest 216 - 10 = 206 events are favorable.\r\n" );
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document.write( "Therefore, the probability under the question is  P = \"206%2F216\" = \"103%2F108\" = 0.9537 = 95.37%.    ANSWER\r\n" );
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