document.write( "Question 1157684: Three dice are tossed. Find the probability of rolling a sum greater than 5. \n" ); document.write( "
Algebra.Com's Answer #780572 by Edwin McCravy(20056)\"\" \"About 
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Three dice are tossed. Find the probability of rolling a sum greater than 5.
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document.write( "We find the probability of the complement and subtract from 1.\r\n" );
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document.write( "There are only 10 possible rolls with sums that are NOT greater than 5.\r\n" );
document.write( "They are these:\r\n" );
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document.write( " 1.  (1,1,1)\r\n" );
document.write( " 2.  (1,1,2)\r\n" );
document.write( " 3.  (1,1,3)\r\n" );
document.write( " 4.  (1,2,1)\r\n" );
document.write( " 5.  (1,2,2)\r\n" );
document.write( " 6.  (1,3,1)\r\n" );
document.write( " 7.  (2,1,1)\r\n" );
document.write( " 8.  (2,1,2)\r\n" );
document.write( " 9.  (2,2,1)\r\n" );
document.write( "10.  (3,1,1)\r\n" );
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document.write( "So the numerator (before reducing) of the probability of the complement event\r\n" );
document.write( "is 10.\r\n" );
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document.write( "We calculate the number of ways the dice can land.\r\n" );
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document.write( "The first one can land any of 6 ways.\r\n" );
document.write( "For every way the first one can land, the second one can land 6 ways.\r\n" );
document.write( "So the first two can land 6∙6 or 36 ways.\r\n" );
document.write( "For every way the first two can land, the third one can land 6 ways.\r\n" );
document.write( "So there are 6∙6∙6 = 36∙6 = 216 ways the three dice can land.\r\n" );
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document.write( "So the denominator (before reducing) of the probability of the complement event\r\n" );
document.write( "is 216.\r\n" );
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document.write( "Edwin
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