document.write( "Question 1157655: Solve this application problem using a system of equations: The owner of Jeremy’s Garage
\n" ); document.write( "wants to fill a 55-gallon drum with a 20% winter mixture of antifreeze for is customers. How
\n" ); document.write( "many gallons of 100% antifreeze should he mix with some 12% antifreeze mixture in order to
\n" ); document.write( "fill the drum?
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Algebra.Com's Answer #780524 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = gallons of 100% antifreeze needed
\n" ); document.write( "Let \"+y+\" = gallons of 12% antifreeze needed
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\n" ); document.write( "The amount of pure antifreeze the owner ends up with will be:
\n" ); document.write( "\"+.2%2A55+=+11+\" gallons
\n" ); document.write( "\"+1%2Ax+%2B+.12y+\" is also the amount of pure antifreeze owner
\n" ); document.write( "ends up with
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+x+%2B+y+=+55+\"
\n" ); document.write( "(2) \"+x+%2B+.12y+=+.2%2A55+\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "(2) \"+x+%2B+.12y+=+11+\"
\n" ); document.write( "(2) \"+100x+%2B+12y+=+1100+\"
\n" ); document.write( "(2) \"+25x+%2B+3y+=+275+\"
\n" ); document.write( "Multiply both sides of (1) by \"+3+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+25x+%2B+3y+=+275+\"
\n" ); document.write( "(1) \"+-3x+-+3y+=+-165+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "\"+22x+=+110+\"
\n" ); document.write( "\"+x+=+5+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+x+%2B+y+=+55+\"
\n" ); document.write( "(1) \"+5+%2B+y+=+55+\"
\n" ); document.write( "(1) \"+y+=+50+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "5 gallons of 100% antifreeze are needed
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\n" ); document.write( "check:
\n" ); document.write( "(2) \"+x+%2B+.12y+=+.2%2A55+\"
\n" ); document.write( "(2) \"+5+%2B+.12%2A50+=+.2%2A55+\"
\n" ); document.write( "(2) \"+5+%2B+6+=+11+\"
\n" ); document.write( "(2) \"+11+=+11+\"
\n" ); document.write( "OK\r
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