document.write( "Question 1157588: please help me with this....Find the​ vertical, horizontal, and oblique​ asymptotes, if​ any, for the given rational function.
\n" ); document.write( "Q(x)=(3x^2-11x-4)/(2x^2-7x-4)
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Algebra.Com's Answer #780478 by greenestamps(13334)\"\" \"About 
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\n" ); document.write( "(1) Horizontal or oblique asymptotes

\n" ); document.write( "The degrees of the numerator and denominator are the same, so there is a horizontal asymptote and no oblique asymptote.

\n" ); document.write( "The ratio of the leading coefficients gives you the horizontal asymptote.

\n" ); document.write( "ANSWER: Horizontal asymptote at y = 3/2.

\n" ); document.write( "(2) Vertical asymptotes

\n" ); document.write( "Vertical asymptotes will occur wherever there is a linear factor in the denominator that is not also in the numerator.

\n" ); document.write( "Factor numerator and denominator:

\n" ); document.write( "\"%28%283x%2B1%29%28x-4%29%29%2F%28%282x%2B1%29%28x-4%29%29\"

\n" ); document.write( "There is a vertical asymptote were the factor (2x+1) in the denominator is equal to 0.

\n" ); document.write( "ANSWER: There is a single vertical asymptote, at x = -1/2.

\n" ); document.write( "What about the factors (x-4) in both numerator and denominator?

\n" ); document.write( "For x=4, the denominator is 0 and so the function is undefined. For all other values of x, the function is equivalent to \"%283x%2B1%29%2F%282x%2B1%29\". So the graph of the given function is the same as the graph of \"3x%2B1%29%2F%282x%2B1%29\" except that there is a hole in the graph at x=4.

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