document.write( "Question 1157574: To get to his parents' house, John must travel at a speed of 60 mph on land and then use a motorboat that travels at a speed of 20 mph in still water. John goes by land to a dock and then travels on a river against a current of 4 mph. He reaches his parent's home in 4.5 hours. The return trip takes him 3.5 hours. How far do his parents live from his house?\r
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Algebra.Com's Answer #780458 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The time spent on land is the same for both legs or the trip. The 1 hour difference between the times for the two legs is the difference in the time going upstream against the current and the time returning downstream with the current.

\n" ); document.write( "The upstream speed is 20-4=16mph; the downstream speed is 20+4-24mph. Determine the distance on the river if the upstream trip takes 1 hour more than the downstream trip.

\n" ); document.write( "\"x%2F16-x%2F24+=+1\"
\n" ); document.write( "\"3x-2x=48\"
\n" ); document.write( "\"x+=+48\"

\n" ); document.write( "The distance on the river is 48 miles.

\n" ); document.write( "Determine the amounts of time for the upstream and downstream trips.

\n" ); document.write( "Upstream: 48/16 = 3 hours
\n" ); document.write( "Downstream: 48/24 = 2 hours

\n" ); document.write( "Determine the distance on land, now knowing that the trip on land took 1.5 hours at 60mph: 1.5(60) = 90

\n" ); document.write( "The total distance is 48+90 = 138 miles.

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