document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157405>Question 1157405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> he needs to make 60 liters of a 36% acid solution to test a new product. His supplier only ships a 10% and 40% solution. he decides to make the 36% solution by mixing the 10% solution with the 40% solution. how much of the 10% solution will he need to use  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780275 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A quick and easy non-algebraic way to solve 2-part mixture problems like this:<br><BR>\n" );
document.write( "(1) 36% is 26/30 of the way from 10% to 40%  (from 10 to 40 is 30; from 10 to 36 is 26...)<BR>\n" );
document.write( "(2) That means 26/30 of the mixture has to be the 40% solution<br><BR>\n" );
document.write( "Since he is making 60 liters of the mixture, he needs 26/30 of 60 liters, or 52 liters, of the 40% solution; the other 8 liters are the 10% solution.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".40(52)+.10(8) = 20.8+0.8 = 21.6<BR>\n" );
document.write( ".36(60) = 21.6<br><BR>\n" );
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