document.write( "Question 1157319: A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 20% real fruit juice and Drink B contains 5% real fruit juice. The company used 56.5 liters of real fruit juice to make 80 more liters of Drink B than liters of Drink A. Write a system of equations that could be used to determine the number of liters of Drink A made and the number of liters of Drink B made. Define the variables that you use to write the system.
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Algebra.Com's Answer #780192 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( " Drink A contains 20% real fruit juice. x liters\r
\n" ); document.write( "\n" ); document.write( " and Drink B contains 5% real fruit juice. y liters\r
\n" ); document.write( "\n" ); document.write( "y=x+80\r
\n" ); document.write( "\n" ); document.write( "20%x +5%y =56.5
\n" ); document.write( "20x+5y==5650\r
\n" ); document.write( "\n" ); document.write( "-x + y = 80.00
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\n" ); document.write( "20x + 5 y = 5650.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -5
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "5.00 x -5.00 y = -400.00
\n" ); document.write( "20.00 x 5.00 y = 5650.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "25.00 x = 5250.00
\n" ); document.write( "/ 25.00
\n" ); document.write( "x = 210.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "-1.00 x + 1.00 y = 80.00
\n" ); document.write( "-210.00 + 1.00 y = 80.00
\n" ); document.write( " 1.00 y = 290.00
\n" ); document.write( " y = 290.00
\n" ); document.write( "Ans x = 210 liters Drink A
\n" ); document.write( " y = 290 liters Drink B
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