\r
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document.write( "Here is the best I could come up with (see CAVEAT near end):\r
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document.write( "
\r
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document.write( "For a=b=c:\r
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document.write( "
\r
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document.write( "So when the numbers are all equal, we get f(a,b,c) = 2. I aim to show that 2 is the minimum value. \r
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document.write( "Let a be the smallest number (due to symmetry, no loss of generality).\r
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document.write( "There are two cases to explore, the first case we let one of the other numbers be bigger than a: \r
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document.write( " 
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document.write( " 
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document.write( "
\r
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document.write( "(f=N/D)
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document.write( "N =
\r
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document.write( "D = 
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document.write( " =
\r
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document.write( "N/D = N*(1/D) =
\r
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document.write( "=
\r
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document.write( "For any
this last expression is > 2. EDIT 4/28: to be precise, it is
\r
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document.write( "
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document.write( "The 2nd case is to let both b and c be larger than a. I am keeping it simple and letting b=c. This is equivalent to writing
,
,
:\r
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document.write( "The resulting N*(1/D) expression is
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document.write( "
and this expression is > 2 as well. EDIT 4/28: the precise value is
\r
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document.write( "
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document.write( "Therefore
\r
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document.write( "CAVEAT:
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document.write( "This proves f_min=2 holds for three of four scenarios: (1)
, (2)
,
, and (3)
,
. My proof does NOT cover the case
, although I'm certain it will hold true. I leave this case to the student (or motivated tutor). To handle this case, let
,
,
. The math will look a lot messier... \r
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document.write( "Perhaps another tutor will find a simpler solution(?) \r
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document.write( "EDIT 4/28: The proof for
is very challenging (at least for me). It has some subtlties that I'm unable to see. Although not a proof, a SPECIFIC EXAMPLE is easy to illustrate:\r
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document.write( "Let a=a
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document.write( " b=2a
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document.write( " c=4a\r
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document.write( "\n" );
document.write( "
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document.write( "= 
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document.write( "= 
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document.write( "= 
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document.write( "= 
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document.write( "=
> 2\r
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document.write( "
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document.write( "