document.write( "Question 1157229: Let a, b, c be positive real numbers. Find the minimum value of
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Algebra.Com's Answer #780119 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Here is the best I could come up with (see CAVEAT near end):\r
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\n" ); document.write( "\n" ); document.write( "For a=b=c:\r
\n" ); document.write( "\n" ); document.write( "\"+f+=+%28%283%2Fa%29%29%2F%28%283%2F2a%29%29+=+%283%2Fa%29%2A%282a%2F3%29+=+2+\"\r
\n" ); document.write( "\n" ); document.write( "So when the numbers are all equal, we get f(a,b,c) = 2. I aim to show that 2 is the minimum value. \r
\n" ); document.write( "\n" ); document.write( "Let a be the smallest number (due to symmetry, no loss of generality).\r
\n" ); document.write( "\n" ); document.write( "There are two cases to explore, the first case we let one of the other numbers be bigger than a: \r
\n" ); document.write( "\n" ); document.write( " \"+a=a+\"
\n" ); document.write( " \"+b=a%2Bepsilon+\"
\n" ); document.write( " \"+c=a+\"\r
\n" ); document.write( "\n" ); document.write( "(f=N/D)
\n" ); document.write( "N = \r
\n" ); document.write( "\n" ); document.write( "D =
\n" ); document.write( " = \"+%286a%2Bepsilon%29%2F%282a%2A%282a%2Bepsilon%29%29+\" \r
\n" ); document.write( "\n" ); document.write( "N/D = N*(1/D) = \r
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\n" ); document.write( "\n" ); document.write( "For any \"epsilon+%3E+0\" this last expression is > 2. EDIT 4/28: to be precise, it is \"+2+%2B+2%2Aepsilon%5E2%2F%28+%286a%5E2%2B7a%2Aepsilon%2Bepsilon%5E2%29+%29+\" \r
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\n" ); document.write( "\n" ); document.write( "The 2nd case is to let both b and c be larger than a. I am keeping it simple and letting b=c. This is equivalent to writing \"+a=b-epsilon\", \"b=b\", \"c=b\":\r
\n" ); document.write( "\n" ); document.write( "The resulting N*(1/D) expression is
\n" ); document.write( " and this expression is > 2 as well. EDIT 4/28: the precise value is \"+2+%2B+2%2Aepsilon%5E2%2F%28+%286b%5E2-7b%2Aepsilon%2Bepsilon%5E2%29+%29+\" \r
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\n" ); document.write( "\n" ); document.write( "Therefore \"+highlight%28+f_min%28a%2Cb%2Cc%29+=+2+%29+\" \r
\n" ); document.write( "\n" ); document.write( "CAVEAT:
\n" ); document.write( "This proves f_min=2 holds for three of four scenarios: (1) \"a=b=c\", (2) \"a%3Cb\", \"c=a\", and (3) \"a%3Cb\", \"b=c\". My proof does NOT cover the case \"a%3Cb%3Cc+\", although I'm certain it will hold true. I leave this case to the student (or motivated tutor). To handle this case, let \"+a=a\", \"+b=a%2Bepsilon\", \"+c+=+a%2Bdelta+\". The math will look a lot messier... \r
\n" ); document.write( "\n" ); document.write( "Perhaps another tutor will find a simpler solution(?) \r
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\n" ); document.write( "\n" ); document.write( "EDIT 4/28: The proof for \"a%3Cb%3Cc+\" is very challenging (at least for me). It has some subtlties that I'm unable to see. Although not a proof, a SPECIFIC EXAMPLE is easy to illustrate:\r
\n" ); document.write( "\n" ); document.write( "Let a=a
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\n" ); document.write( "= \"++%287%2F%284a%29%29+%2F+%28%281%2F%283a%29%29%2B%281%2F%285a%29%29%2B%281%2F%286a%29%29%29+\"
\n" ); document.write( "= \"++%28%287%2F%284a%29%29%29%2F%28%2821%2F%2830a%29%29%29+\"
\n" ); document.write( "= \"++%287%2F4%29+%2A+%2830%2F21%29+\"
\n" ); document.write( "= \"+++2.5+\" > 2\r
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