document.write( "Question 1157276: A pile of 23 coins consists of nickels and dimes. The total value of the coins is $1.20. Find the number of each type of coin \n" ); document.write( "
Algebra.Com's Answer #780111 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) Using formal algebra.... \n" ); document.write( "n nickels \n" ); document.write( "d dimes \n" ); document.write( "n+d=23 [the total number of coins is 23] \n" ); document.write( "5n+10d=120 [the total value of the coins is $1.20 = 120 cents] \n" ); document.write( "Solve the pair of linear equations by your favorite method.... \n" ); document.write( "Note the setup using formal algebra is easier if you start with \n" ); document.write( "n nickels \n" ); document.write( "(23-n) dimes [because the total number of coins is 23] \n" ); document.write( "Then solving the problem involves solving a single equation, instead of a system of two equations: \n" ); document.write( "5(n)+10(23-n) = 120 \n" ); document.write( "(2) Using logical reasoning and simple mental arithmetic (if a formal algebraic solution is not required).... \n" ); document.write( "(a) 23 coins all nickels would make the total value 23*5 = 115 cents; that is 5 cents short of the actual total value \n" ); document.write( "(b) Exchange one of the nickels for a dime; that keeps the total number of coins 23 and increases the total value by 5 cents -- giving us the actual total value of 120 cents \n" ); document.write( "ANSWER: 22 nickels and 1 dime \n" ); document.write( " \n" ); document.write( " |