document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157274>Question 1157274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Rosoff works in the lab at a pharmaceutical company. He needs to make 60 liters of a 13% acid solution to test a new product. His supplier only ships a 16% and a 12% solution. Mr. Rosoff decides to make the 13% solution by mixing the 16% solution with the 12% solution. How much of the 16% solution will Mr. Rosoff need to use?\r<BR>\n" );
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document.write( "[A] 10 L [B] 60 L [C] 45 L [D] 15 L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780102 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=16% sol in l<BR>\n" );
document.write( "60-x= 12% sol <BR>\n" );
document.write( "60*0.13=7.8 liter of pure acid<BR>\n" );
document.write( ".16x+.12(60-x)=7.8<BR>\n" );
document.write( ".16x+7.2-.12x=7.8<BR>\n" );
document.write( "0.04x=0.6<BR>\n" );
document.write( "=15 liters of 16%<BR>\n" );
document.write( "D\r<BR>\n" );
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document.write( "Notice that 13% is 1/4 of the way from 12 to 16%<BR>\n" );
document.write( "That means 3/4 of the acid is weighted for 12% of 45 l, leaving 15 l for 16% </SPAN>\n" );
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