document.write( "Question 1157242: If 8 persons are seated at a random in a row. What is the probability that a certain couple
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Algebra.Com's Answer #780084 by ikleyn(52908)\"\" \"About 
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document.write( "In all, there are 8! = 8*7*6*5*4*3*2 = 40320 permutations of 8 objects.\r\n" );
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document.write( "If two of them are together, we consider them as one item, and then we have, actually, 7! = 7*6*5*4*3*2 = 5040 different \r\n" );
document.write( "permutations for seven items, and two permutations inside this par; \r\n" );
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document.write( "so, in all, there are 2*7! permutations for these 8 persons, where these two are together.\r\n" );
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document.write( "Therefore, the answers are\r\n" );
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document.write( "(a)  P = \"%282%2A7%21%29%2F8%21\" = \"%282%2A5040%29%2F40320\" = \"2%2F8\" = \"1%2F4\" = 0.25;\r\n" );
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document.write( "(b)  P =  1 - \"1%2F4\" = \"3%2F4\" = 0.75.\r\n" );
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\n" ); document.write( "\n" ); document.write( "On Permutations,  see introductory lessons \r
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\n" ); document.write( "\n" ); document.write( "    - OVERVIEW of lessons on Permutations and Combinations\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic  \"Combinatorics: Combinations and permutations\". \r
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\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
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