document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1157207>Question 1157207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A crew of 2 could put siding on a house in 30 hours. Another crew of 3 could do the same job in 24 hours. How long would it take all 5 people working together?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #780048 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=780048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is alternative to the standard algebraic solution method shown by the other tutor.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times: the LCM of 24 and 30 is 120.<br><BR>\n" );
document.write( "In 120 hours, the crew of 2 could put siding on 120/30 = 4 houses; the crew of 3 could put siding on 120/24 = 5 houses.  So in 120 hours the two crews together could put siding on 4+5=9 houses.<br><BR>\n" );
document.write( "So the number of hours it would take the two crews together to put siding on 1 house is 120/9 = 40/3, or 13 1/3 hours, or 13 hours 20 minutes.<br><BR>\n" );
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