document.write( "Question 1157206: A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 40% and the third contains 60%. He wants to use all three solutions to obtain a mixture of 84 liters containing 50% acid, using 3 times as much of the 60% solution as the 40% solution. How many liters of each solution should be used? \n" ); document.write( "

Algebra.Com's Answer #780031 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "        VOLUME    PURE ACID\r\n" );
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document.write( "20%        x       0.2x\r\n" );
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document.write( "40%        y       0.4y\r\n" );
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document.write( "60%       3y      0.6*3y\r\n" );
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document.write( "50%       84\r\n" );
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\n" ); document.write( "\n" ); document.write( " $\"system%28x%2B4y=84%2C0.2x%2B2.2y=0.5%2A84%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"system%28x%2B4y=84%2Cx%2B11y=210%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"E2-E1\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"7y=126\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28y=18%29\"$ , and you can find the other two. \n" ); document.write( "

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