document.write( "Question 1156951: Find the equation of the line tangent to the curve at the point defined by the given value of t.
\n" ); document.write( "\"x=16sint\", \"y=4cost\", \"t=pi%2F4\"
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Algebra.Com's Answer #780026 by Alan3354(69443)\"\" \"About 
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Find the equation of the line tangent to the curve at the point defined by the given value of t.
\n" ); document.write( "\"x=16sint\", \"y=4cost\", \"t=pi%2F4\"
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\n" ); document.write( "\"x=16sint\" ---> @ pi/4 = 8sqrt(2)
\n" ); document.write( "\"y=+4cost\" ---> @ pi/4 = 2sqrt(2)\r
\n" ); document.write( "\n" ); document.write( "dx/dt = 16cos(t) ---> @ pi/4 = 8sqrt(2)
\n" ); document.write( "dy/dt = -4sin(t) ---> @ pi/4 = -2sqrt(2)
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\n" ); document.write( "dy/dx = -sin(t)/(4cos(t)) = -tan(t)/4
\n" ); document.write( "@pi/4: dy/dx = -1/4
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\n" ); document.write( "\"y+-+2sqrt%282%29+=+%28-1%2F4%29%2A%28x+-+8sqrt%282%29%29\"
\n" ); document.write( "\"y+-+2sqrt%282%29+=+%28-x%2F4%29+%2B+2sqrt%282%29%29\"
\n" ); document.write( "\"y+=+%28-x%2F4%29+%2B+4sqrt%282%29%29\"
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