document.write( "Question 1157181: Total profit P is the difference between total revenue R and total cost C. Given the following​ total-revenue and​ total-cost functions, find the total​ profit, the maximum value of the total​ profit, and the value of x at which it occurs.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "Upper R left parenthesis x right parenthesis equals 1200 x minus x squared
\n" ); document.write( "R(x)=1200x−x2​,
\n" ); document.write( "Upper C left parenthesis x right parenthesis equals 3000 plus 20 x
\n" ); document.write( "C(x)=3000+20x
\n" ); document.write( "

Algebra.Com's Answer #780008 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
r(x) = 1200x - x^2
\n" ); document.write( "c(x) = 3000 + 20x
\n" ); document.write( "p(x) = r(x) - c(x)
\n" ); document.write( "that becomes:
\n" ); document.write( "p(x) = 1200x - x^2 - (3000 + 20x)
\n" ); document.write( "simplify to get:
\n" ); document.write( "p(x) = 1200x - x^2 - 3000 - 20x
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "p(x) = -3000 + 1180x - x^2
\n" ); document.write( "order the terms in descending order of degree to get:
\n" ); document.write( "p(x) = -x^2 + 1180x - 3000
\n" ); document.write( "a = the coefficient of the x^2 term = -1
\n" ); document.write( "b = the coefficient of the x term = 1180
\n" ); document.write( "c = the constant term = -3000
\n" ); document.write( "the maxim profit is when x = -b/2a.
\n" ); document.write( "that becomes x = -1180/-2 = 590.
\n" ); document.write( "the maximum profit is the value of the equation at x = 590
\n" ); document.write( "that becomes p(x) = 345,100
\n" ); document.write( "that's your solution.
\n" ); document.write( "here's the graph that confirms that.
\n" ); document.write( "\"$$$\"
\n" ); document.write( "
\n" ); document.write( "
\n" );