document.write( "Question 15821: a boat travels 80km upstream and then returns to its starting point. The entire trip takes 3.6h. if the speed of the current is 10km/h, determine the speed of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #7800 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = speet of the boat in still water. \n" ); document.write( "x+10 = speed of the boat going downstream. \n" ); document.write( "x-10 = speed of the boat going upstream.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is based upon the time of the boat to go upstream and then downstream. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time upstream = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Total time = Time up + Time down = 3.6 hours \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the LCD = (x-10)(x+10), and the result is:\r \n" ); document.write( "\n" ); document.write( "80(x+10) + 80(x-10) = 3.6(x-10)(x+10)\r \n" ); document.write( "\n" ); document.write( "80x +800 + 80x - 800 = 3.6(x^2 - 100) \n" ); document.write( "160x = 3.6x^2 - 360\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Set equal to zero, since it is a quadratic equation: \n" ); document.write( "0 = 3.6x^2 - 160x - 360\r \n" ); document.write( "\n" ); document.write( "Use quadratic equation solver or calculator:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x must be a postive number, so forget the negative value, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x+10 = 56.49 mph downstream \n" ); document.write( "x-10 = 36.49 mph upstream\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As a check, calculate the equation for time upstream and downstream: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |