document.write( "Question 15821: a boat travels 80km upstream and then returns to its starting point. The entire trip takes 3.6h. if the speed of the current is 10km/h, determine the speed of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #7800 by rapaljer(4671)\"\" \"About 
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Let x = speet of the boat in still water.
\n" ); document.write( "x+10 = speed of the boat going downstream.
\n" ); document.write( "x-10 = speed of the boat going upstream.\r
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\n" ); document.write( "\n" ); document.write( "The equation is based upon the time of the boat to go upstream and then downstream. \r
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\n" ); document.write( "\n" ); document.write( "Time upstream = \"D%2Fr\" Time downstream = \"D%2Fr\"\r
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\n" ); document.write( "\n" ); document.write( "Total time = Time up + Time down = 3.6 hours
\n" ); document.write( "\"80%2F%28x-10%29+%2B+80%2F%28x%2B10%29+=+3.6+\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the LCD = (x-10)(x+10), and the result is:\r
\n" ); document.write( "\n" ); document.write( "80(x+10) + 80(x-10) = 3.6(x-10)(x+10)\r
\n" ); document.write( "\n" ); document.write( "80x +800 + 80x - 800 = 3.6(x^2 - 100)
\n" ); document.write( "160x = 3.6x^2 - 360\r
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\n" ); document.write( "\n" ); document.write( "Set equal to zero, since it is a quadratic equation:
\n" ); document.write( "0 = 3.6x^2 - 160x - 360\r
\n" ); document.write( "\n" ); document.write( "Use quadratic equation solver or calculator:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28160+%2B-+sqrt%28+160%5E2%2B4%2A3.6%2A360+%29%29%2F%282%2A3.6%29+\"
\n" ); document.write( "\"x+=+%28160+%2B-+sqrt%2830784%29%29%2F+7.2+\"
\n" ); document.write( "\"x+=+%28160+%2B-+175.4537%29%2F7.2+\" (approximately!)\r
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\n" ); document.write( "\n" ); document.write( "x must be a postive number, so forget the negative value,
\n" ); document.write( "\"x=+%28160+%2B+175.4537%29%2F7.2\"
\n" ); document.write( "\"x+=+46.49+\"mph in still water.
\n" ); document.write( "x+10 = 56.49 mph downstream
\n" ); document.write( "x-10 = 36.49 mph upstream\r
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\n" ); document.write( "\n" ); document.write( "As a check, calculate the equation for time upstream and downstream:
\n" ); document.write( "\"80%2F36.49+%2B+80%2F56.49\". The answer comes out to about 3.6 hours.\r
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