document.write( "Question 1157115: A toy rocket is launched from the top of a building 114 feet tall at an initial velocity of 167 feet per second
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document.write( "a) give the function that describes the height of the rocket in terms of time t
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document.write( "b) determine the time at which the rocket reaches its maximum height, and the maximum height in feet
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document.write( "c) for what time interval will the rocket be more than 122 feet above ground level
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document.write( "d) after ho many seconds will it hit the ground?\r
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document.write( "the function that describes the height of the rocket in terms of t is s(t)= \n" );
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Algebra.Com's Answer #779920 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The function is f(t)= -16t^2+167t+114, the first for acceleration due to gravity, the second for initial speed, the third for initial height. \n" ); document.write( "maximum height t is -b/2a or -167/-32-5.22 sec \n" ); document.write( "height is 549.76 feet using 5.22. \n" ); document.write( "set the equation = to 122 \n" ); document.write( "then it becomes -16t^2+167t-8=0 \n" ); document.write( "t=(-167+/- sqrt (167^2-512)/-32; sqrt term is 27377 and that equals+/- 165.46 \n" ); document.write( "t=-1.54/-32 or 0.048 sec \n" ); document.write( "t=-332.46/-32 or 10.39 sec \n" ); document.write( "That interval is 10.34 sec (rounded)\r \n" ); document.write( "\n" ); document.write( "hits the ground when original equation equals 0. \n" ); document.write( "t=(-167+/- sqrt (35185))/-32; -167+/-187.58=-354.58 \n" ); document.write( "divide by -32 and \n" ); document.write( "t=11.08 sec\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |